Ya idk I was thinking like ok out of 12 possible options there's one 6 that can be rolled on the first one and three in the 2nd one LOL BUT IDEK LIKE WHAT THAT EQUASION WOULD LOOK LIKE?? 1/12 + 3/12?? I don't remember that ever being a way to do probability ugh @ridstee
ok so lets assume that the 2nd die is also 6 sided. that means 3/6 can be a six which is the same as 1/2. the other die is a regular so thats 1/6 chance. because they are independent of each other we just add them together which is 4/6 (the denominator does not change).
your odds are 4/6 which is the same as 2/3.... i think...
im thinking if you roll them 36 times, the odds are 18 rolls have a 6 from the weighted die
and 6 have a 6 from the regular die, so you'd think it'd be 24/36 or 2/3 BUT 3 of those rolls would have 2 6's so it adjusts your calculations so actually 21/36 rolls would have a 3 in it, in the long run. So I think those are the odds of getting a 6?
unless you arent rolling both dice, you're just picking one at random. Then there's a 50% chance of getting 1/2 odds (which comes to 1/4 odds, or 3/12) and a 50% chance of getting 1/6 odds (which is 1/12 odds). Then if you add those odds together you have 1/12 + 3/12 = 4/12 which can be reduced to 1/3 which is i think what you're looking for